Question

Suppose you synthesized a Salt with formula Ni(en)2(H2O)2SO4•5H2O. In your synthesis you used 0.014mol of NiSO4.6H2O and 0.007mol of en. The actual yield (salt weighed out after synthesis) is 0.92g. Calculate the percent yield. Report your answer in % but don't report the units (e.g. 58 for 58%)

Answer 1

standard reaction predicts that 1 mole NiSO4. 6H2O reacts 2 mole en.

now, the supplide data provide the information that 0.007 mole en is the limiting reagent and it will produce 0.0035 mole salt ( standard reaction: 2 mole en produces 1 mole salt)

molecular weight of salt = 339.5564 gm /mole

hence, weight of 0.0035 mole (theoretical yield) = 339.5564 gm /mole * 0.0035 mole = 1.19 gm

% yield = (actual yield / theoretical yield )*100 = (0.92 gm / 1.19 gm ) *100 = 77.3 %