Question

Part A

Sort the following transitions from an excited state to a ground state according to the series into which they fall.

Drag the appropriate transitions to their respective bins.

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The transition from n=4 to n=1corresponds to the transition of an electron from the fourth energy shell to the first energy shell. Thus, in the given transition, the lowest energy shell (or ground state) is the first shell. This transition occurs in the Lyman series.

The energy difference between two energy shells

The energy difference between two energy shells is calculated using the formula

ΔE=Ef−Ei

where Ef       is the energy of the final shell, and Ei is the energy of the initial shell from which the transition occurs. For example, for the transition n=4 to n=1, the initial shell is the fourth shell, and the final shell is the first shell. Thus, the change in energy between the fourth and the first shell is denoted as ΔE=E1−E4. The energy corresponding to a shell is calculated using

En=−2.179×10−18/(n)2 J

where n is the shell number.

Part B - Calculate the energy difference

Calculate the energy difference for a transition in the Paschen series for a transition from the higher energy shell n=4.

Express your answer to four significant figures and include the appropriate units.

−1.059×10⁻¹⁹ J

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The energy difference between the third shell and the fourth shell is calculated as

ΔE=E3−E4                                            =−0.2421×10−18−(−1.362×10−19) J                =−1.059×10−19J

The energy difference between a higher energy shell and a lower energy shell is the amount of energy released when an electron undergoes a transition between the two shells.
To conserve this emitted energy, a photon of equal energy is emitted. Thus,

Ephoton=−ΔE

The negative sign of the energy difference between two shells implies that energy is lost when an electron undergoes a transition from a higher energy shell to a lower energy shell.

Significant Figures Feedback: Your answer −1.0573⋅10−19J was either rounded differently or used a different number of significant figures than required for this part.

Part C

Calculate the wavelength of the photon emitted when an electron makes a transition from n=4 to n=3. You can make use of the following constants:

h=6.626×10−34 J⋅s

c=2.998×108 m/s

1 m=109 nm

Express your answer to four significant figures and include the appropriate units.

λ=

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Answer 1

part C )   i think this is part you need.

n1 = 3

n2 = 4

formula :

1/      = R_H [1/n₁² - 1/n₂²]

           = 1.097 x 10^7 [1/3^2 - 1/4^2]

          = 1.097 x 10^7 [1/9 - 1/16]

          = 5.33 x 10^5 m^-1

= 1/ 5.33 x 10^5 m^-1

     = 1.875 x 10^-6 m

wave length = = 1875 nm