Question

You are given a 0.265 wt% stock solution of Disopyramide in a forensic solvent (mixture of...

You are given a 0.265 wt% stock solution of Disopyramide in a forensic solvent (mixture of water & methanol containing acetic acid & triethyamine). The density of the solution is 0.958 g/mL. What is the concentration of disopyramide in this stock solution in μg/μL? (μL refers to the whole solution, not only the solvent) State your answer using the correct number of significant figures.

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Answer #1

find concentratino of disopyramide

assume a basis of 1 liter so

1 L = 1000 mL

mass of solution = 0.958 g/mL * 1000 mL = 958 g

mass of disopyramide = 0.265 /100 * 958 = 2.5387 g of disopyramide  

now,

micrograms =2.5387 g of disopyramide = 2.5387 *10^6 micro grams

V = 1 L = 10^6 microliters

concentration in microgram/microL = (2.5387 *10^6) / (10^6 ) = 2.5387 microgram/microliter

correct sig fig --> must be 3, so 2.5387 --> 2.54 microgram/microliter

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