2NH3(g) +3O2(g) +2CH4(g) →2HCN(g) + 6H2O(g)2NH3(g) + 3O2(g) + 2CH4(g) →2HCN(g) + 6H2O(g)
If 3.84 moles of methane are consumed in this reaction, how many moles of HCN will be produced?
If 25.1 g of ammonia are reacted, how many grams of HCN will be produced?
If I react 48.3 g of ammonia with 32.4 g of methane (assume oxygen is present in excess), what is the maximum mass of HCN that can be produced?
If I react 17.9 g of ammonia with excess oxygen and methane, but only collect 23.3 g of HCN, what is the percent yield?
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