Question

Explain why an optically inactive product is obtained when (-)-3-ethyl-1-hexene undergoes catalytic hydrogenation

Explain why an optically inactive product is obtained when (-)-3-ethyl-1-hexene undergoes catalytic hydrogenation

Homework Answers

Answer #1

Solution :-

When the (-)-3-ethyl-1-hexene undergoes the catalytic hydrogenation reaction then H-2 molecule is added across the double bond which causes it to have two same groups in the structure. As we know when the 4 different substituent groups are attached to the carbon then it is chiral carbon and shows optical activity.

But because of the catalytic hydrogenation process the chiral center is no longer present in the product molecule therefore it does not show any optical activity.

Therefore we can say that catalytic hydrogenation causes the loss of chiral center in the product therefore it becomes optically inactive.

Following image shows the reaction equation.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Car-3-ene undergoes catalytic hydrogenation to give only one of two possible stereoisomeric products. The product has...
Car-3-ene undergoes catalytic hydrogenation to give only one of two possible stereoisomeric products. The product has the common name cis-carane indicating the methyl group and the cyclopropane ring are cis to each other. Suggest an explanation for this stereochemical outcome. (The other product, which is not formed would be trans-carane.)
Two stereoisomers are obtained from the reaction of HBr with (3S,4S)-4-bromo-3-methyl-1-pentene.1 Propose a mechanism for the...
Two stereoisomers are obtained from the reaction of HBr with (3S,4S)-4-bromo-3-methyl-1-pentene.1 Propose a mechanism for the reaction(provide a three-dimentional representation of the intermediates).Draw the structure of the two stereoisomers that form,showing stereochemistry of the new chiral centre.2. one of the stereoisomers is optically inactive.circle the optically inactive compound and explain why it is optically inactive.
What product is obtained when you epoxidize (d)-(+)-carvone with mcpba? Why do you obtain this product?
What product is obtained when you epoxidize (d)-(+)-carvone with mcpba? Why do you obtain this product?
What are the products generated when 3-methyl-1-butene undergoes (a) acid-catalyzed hydroboration (b) oxymercuration-reduction. Explain their differences.
What are the products generated when 3-methyl-1-butene undergoes (a) acid-catalyzed hydroboration (b) oxymercuration-reduction. Explain their differences.
1. Explain why businesses produce more of a product when the price rises. 2. Explain how...
1. Explain why businesses produce more of a product when the price rises. 2. Explain how inflation reduces the purchasing power of consumers.
Problem set for Competitive Nucleophiles 1) Why does water always enter the bottom of the condenser...
Problem set for Competitive Nucleophiles 1) Why does water always enter the bottom of the condenser and exit from the top? 2) Why are boiling stones added to the solvent undergoing reflux? 3) Why are any large clumps of ammonium salts broken down into a powder? 4) Why is it necessary to perform the competing nucleophiles reactions under acidic conditions? 5) Which is the better nucleophile, fluoride or iodide ion? Explain this in the terms of the nature of the...
Pre-lab questions for Bromination of trans-Cinnamic Acid to 2,3-dibromo-3-Phenylpropanoic Acid. 1. Why should you add more...
Pre-lab questions for Bromination of trans-Cinnamic Acid to 2,3-dibromo-3-Phenylpropanoic Acid. 1. Why should you add more Br2 to the reaction mixture if it turns colorless during the course of the reaction? 2. Predict the products likely to be formed via the anti- addition of Br2/Dichloromethane to trans- cinnamic acid. 3. Based on your answer to Q2 above, what is the predicted m.p. of the brominated product(s) you will prepare via this method? 4. Would you expect the product mixture you...
The test statistic of z= −2.45 is obtained when testing the claim that p= 2/3. 1.)...
The test statistic of z= −2.45 is obtained when testing the claim that p= 2/3. 1.) Using a significance level of α= 0.05​, find the critical​ value(s). Can someone explain how to find the answer step by step without a calculator, I'm Completely lost with the fraction.
b. Draw the product obtained when D-tagatose reacts with H2 and Pt.             c. D-tagatose is...
b. Draw the product obtained when D-tagatose reacts with H2 and Pt.             c. D-tagatose is a reducing sugar. Explain how this can be the case.             d. Draw the monosaccharide derivative(s) formed when D-tagatose reacts with      Benedict’s reagent.             e. Draw and name the enantiomer of D-tagatose.             f. Draw a diastereomer of D-tagatose that is a D-sugar, but is not D-fructose.             g. Draw a-D-tagatofuranose.             h. Draw b-D-tagatofuranose.             i. Is a-D-tagatofuranose a reducing sugar? Why...
1. The following data were obtained from a Charpy impact test for a ductile cast iron...
1. The following data were obtained from a Charpy impact test for a ductile cast iron containing 2.55 wt% Si. Plot the data and find the ductile to brittle transition temperature. What does this transition temperature signify? Would you use this material in a product that undergoes constant impact forces below 0oC? Why or why not? Explain. Use graph supplied on next page. TEST TEMPERATURE (oC) IMPACT ENERGY (ft-lb) -50 4 -20 4 0 6.4 8 8.8 14 12 20...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT