For a closed aqueous solution at pH 8.4, the bicarbonate species concentration is measured as 10-2.9 M. Calculate the concentrations of all carbonate system species, and the total dissolved inorganic carbon concentration in the system in moles/L, mg/L, and mg C/L.
Given, Concentration of HCO3- ion = 10-2.9 M approx 10-3 M at pH= 8.4.
Therefore, In 1 litre solution, [HCO3-] = 10-3 × 1 mol
= 10-3 mol
Here, H2CO3 (pka1) HCO3- (pka2) CO32-
pka2= 10.32 (from data table of pka value of different ions )
From Henderson Hassel back Equation:
pH= pka2 + log[CO32-]/[HCO3-]
8.4= 10.32+ log[CO32-]/10-3
-1.92= log[CO32-]/10-3
[CO32-]= 10-1.92 × 10-2.9 M
= 10-4.82 M
Now, molar weight of CO32- = 60 grams
Molar weight of HCO3- = 61 grams
Therefore, moles of [HCO3-] + [CO32-] in 1 litre solution
= 10-2.9 M × 1 litre + 10-4.82 M × 1 litre.
= Total dissolved inorganic carbon content
(As both [HCO3-] and [CO32-] have one C atom each)
= (10-2.9 + 10-4.82 ) moles inorganic carbon content.
= (10-2.9 + 10-4.82) × 12× 1000 mg/L
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