Question

What is the expected yield of this reaction assuming 0.230 g of acetaminophen is used along with all of the other starting amounts of reagents listed in this experiment? Your answer should be in grams and answer to the 3rd decimal place.

Reagents and Solvents	MW g/mol	Density g/mL	Amount	mmol	Boiling point (C)	Melting point (C)
Acetaminophen	151.163	1.293	0.23 g		420	169
K2CO3	138.205	2.43	0.42 g		decomposes	891
Iodoethane	155.97	1.940	160 uL		70-73	-111 – -167
2-butanone	72.11	0.805	2.5 mL		79.6	-87
Dichloromethane	84.93	1.325	5 mL		40	-97
Acetone	58.08	0.791	1-2 mL		56	-94
Phenacetin	179.22	1.1248	5 mL		132	132-133

Answer 1

Solution

In the preparation of Phenacetin, 0.23 g of Acetaminophen is used which is the key starting material.

The number of mmoles of Acetaminophen = 0.23 g / 151.163 g/mol = 0.00152 mol

Thus, number of moles of Acetaminophen used = number of moles of phenacetin formed

= 0.00152 mol

Mass of phenacetin formed = 0.00152 mol x molecular wt of phenacetin = 0.00152 mol x 179.22 g/mol

= 0.273 g

Thus, the expected yield for the conversion of Acetaminophen to phenacetin = 0.273 g Ans