Question

A 2.1782.178 g sample of a solid mixture containing only potassium carbonate (MM=138.2058 g/mol) and potassium...

A 2.1782.178 g sample of a solid mixture containing only potassium carbonate (MM=138.2058 g/mol) and potassium bicarbonate (MM=100.1154 g/mol) is dissolved in distilled water. A volume of 35.59 of a 0.763 M HCl standard solution is required to titrate the mixture to a bromocresol green end point. Calculate the weight percent of potassium carbonate and potassium bicarbonate in the mixture.

K2CO3:________________________

KHCO3:__________________________

Science   Chemistry   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

weight percent of KHCO3 in the mixture = 44.72% (approx)

weight percent of K2CO3 in the mixture = 55.28 % (approx)

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
2.176 g of a solid mixture containing only potassium carbonate (FW = 138.2058 g/mol) and potassium...
2.176 g of a solid mixture containing only potassium carbonate (FW = 138.2058 g/mol) and potassium bicarbonate (FW = 100.1154 g/mol) is dissolved in distilled water. 30.06 mL of a 0.765 M HCl standard solution is required to titrate the mixture to a bromocresol green end point. Calculate the weight percent of potassium carbonate and potassium bicarbonate in the mixture.
2.164 g of a solid mixture containing only potassium carbonate (FW = 138.2058 g/mol) and potassium...
2.164 g of a solid mixture containing only potassium carbonate (FW = 138.2058 g/mol) and potassium bicarbonate (FW = 100.1154 g/mol) is dissolved in distilled water. 32.22 mL of a 0.766 M HCl standard solution is required to titrate the mixture to a bromocresol green end point. Calculate the weight percent of potassium carbonate and potassium bicarbonate in the mixture.
A 0.5242 g solid sample containing a mixture of LaCl3 (molar mass = 245.26 g/mol) and...
A 0.5242 g solid sample containing a mixture of LaCl3 (molar mass = 245.26 g/mol) and Ce(NO3)3 (molar mass = 326.13 g/mol) was dissolved in water. The solution was titrated with KIO3, producing the precipitates La(IO3)3(s) and Ce(IO3)3(s). For the complete titration of both La3 and Ce3 , 42.70 mL of 0.1237 M KIO3 was required. Calculate the mass fraction of La and Ce in the sample.
A 10.231-g sample of window cleaner containing ammonia was diluted with 39.466 g of water. Then...
A 10.231-g sample of window cleaner containing ammonia was diluted with 39.466 g of water. Then 4.373 g of solution was titrated with 14.22 mL of 0.1063 M HCl to reach a bromocresol green end point. a.) What fraction of the 10.231-g sample of window cleaner is contained in the 4.373 g that was analyzed? b) How many grams of NH3 (MW 17.031) were in the 4.373-g sample? c) Find the weight percent of NH3 in the cleaner.
In a sodium carbonate/ bicarbonate analysis a 0.4057g sample required 15.65 ml of 0.1690M HCL solution...
In a sodium carbonate/ bicarbonate analysis a 0.4057g sample required 15.65 ml of 0.1690M HCL solution to reach the phenophthalein end point and a total of 40.30ml to achieve the bromocresol green endpoint. detemine the wt% NaHCO3 anf Na2CO3 in this sample. formula weights of NaHCO3 and Na2CO3, respectively are 84.0 and 106.0g/mol
Assuming you weighed out a 2.3684 g sample of your unknown, and dissolved and diluted it...
Assuming you weighed out a 2.3684 g sample of your unknown, and dissolved and diluted it as in the procedure below, and it took 35.63 mL of a 0.1025 M HCl titrant to reach the endpoint, what are the weight percents of Na2CO3 and NaHCO3 in your unknown sample? Hints: -Set g Na2CO3 = X -Eqn A: bicarbonate + carbonate = diluted weighted mass (remember, the mass is not 2.3684, you diluted it before you titrated it.Calculate the diluted g...
A solution is prepared by dissolving 11.3 g of a mixture of sodium carbonate and sodium...
A solution is prepared by dissolving 11.3 g of a mixture of sodium carbonate and sodium bicarbonate in 1.00 L of water. A 300.0 cm3 sample of the solution is then treated with excess HNO3 and boiled to remove all the dissolved gas. A total of 0.940 L of dry CO2 is collected at 298 K and 0.972 atm. Find the molarity of the carbonate in the solution and the molarity of the bicarbonate in the solution.
A solution is prepared by dissolving 11.6 g of a mixture of sodium carbonate and sodium...
A solution is prepared by dissolving 11.6 g of a mixture of sodium carbonate and sodium bicarbonate in 1.00 L of water. A 300.0 cm3 sample of the solution is then treated with excess HNO3 and boiled to remove all the dissolved gas. A total of 0.940 L of dry CO2 is collected at 298 K and 0.972 atm. 1.Find the molarity of the carbonate in the solution. 2.Find the molarity of the bicarbonate in the solution.
Ag+ + Cl- ↔ AgCl(s) 1.004 g of an impure mixture containing Cl- was dissolved to...
Ag+ + Cl- ↔ AgCl(s) 1.004 g of an impure mixture containing Cl- was dissolved to 100.0 mL. 10.00 mL of this solution required 22.97 mL of 0.05274 M AgNO3 to reach end point. What is the weight percent of Cl- in the unknown solid?
A 0.6113 g mixture of KCN (MW = 65.116 g/mol) and NaCN (MW = 49.005 g/mol)...
A 0.6113 g mixture of KCN (MW = 65.116 g/mol) and NaCN (MW = 49.005 g/mol) was dissolved in water. AgNO3 was added to the solution, precipitating all the CN– in solution as AgCN (MW = 133.886 g/mol). The dried precipitate weighed 1.421 g. Calculate the weight percent of KCN and NaCN in the original sample.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT