Question

In a sodium carbonate/ bicarbonate analysis a 0.4057g sample required 15.65 ml of 0.1690M HCL solution...

In a sodium carbonate/ bicarbonate analysis a 0.4057g sample required 15.65 ml of 0.1690M HCL solution to reach the phenophthalein end point and a total of 40.30ml to achieve the bromocresol green endpoint. detemine the wt% NaHCO3 anf Na2CO3 in this sample. formula weights of NaHCO3 and Na2CO3, respectively are 84.0 and 106.0g/mol

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Carbonic acid (H2CO3) is a weak diprotic acid with Ka1=4.43�10^-7 and Ka2=4.73�10^-11. When sodium bicarbonate (NaHCO3)...
Carbonic acid (H2CO3) is a weak diprotic acid with Ka1=4.43�10^-7 and Ka2=4.73�10^-11. When sodium bicarbonate (NaHCO3) is titrated with hydrochloric acid (HCl), it acts as a weak base according to the equation NaHCO3(aq)+HCl(aq)?H2CO3(aq)+NaCl(aq) 1)What volume of 0.180M HCl is required for the complete neutralization of 1.50g of NaHCO3 (sodium bicarbonate)? 2)What volume of 0.120M HCl is required for the complete neutralization of 1.10g of Na2CO3 (sodium carbonate)? 3)A sample of NaOH (sodium hydroxide) contains a small amount of Na2CO3 (sodium...
An experiment was to identify the unknown solution as sodium carbonate or sodium bicarbonate by reacting...
An experiment was to identify the unknown solution as sodium carbonate or sodium bicarbonate by reacting it with HCl and taking pressure measurements. My chemical equations are: NaHCO3+HCl--->CO2+H2O+NaCl Na2CO3+2HCl--->CO2+H2O+2NaCl. The instructor said that it can be determined by looking at the chemical equation. My response was the pressure measurements were from the unknown were closer to sodium bicarbonate than sodium carbonate. Is this a correct assumption?
Part A: What volume of 0.100 M HCl is required for the complete neutralization of 1.50...
Part A: What volume of 0.100 M HCl is required for the complete neutralization of 1.50 g of NaHCO3 (sodium bicarbonate)? Part B: What volume of 0.140 M HCl is required for the complete neutralization of 1.30 g of Na2CO3 (sodium carbonate)? Part C: A sample of NaOH (sodium hydroxide) contains a small amount of Na2CO3 (sodium carbonate). For titration to the phenolphthalein endpoint, 0.200 g of this sample requires 23.98 mL of 0.100 M HCl . An additional 0.700...
"A solution that possibly contains NaOH, Na2CO3, or NaHCO3 either alone or in a compatible combination...
"A solution that possibly contains NaOH, Na2CO3, or NaHCO3 either alone or in a compatible combination is analyzed by titration with 0.1202 M HCl. The first titration uses 25.00 mL of the sample solution and requires 15.67 mL of HCl to reach a phenolphthalein end-point. The second titration uses another 25.00 mL portion of the sample and requires 42.13 mL of HCl to reach a bromocresol green end-point. Calculate the number of milligrams of each solute per milliliter of solution....
A 0.605 gm sample of Sodium Carbonate and Sodium bicarbonate , the solution titrated with 0.106N...
A 0.605 gm sample of Sodium Carbonate and Sodium bicarbonate , the solution titrated with 0.106N HCI , 40.2 ml needed from the titrant to reach phenolphthalein , and when titrated in presence of blue bromophenol found the total acid volume is 95.4 ml . calculate the % for the constituents ?
Sodium carbonate, Na2CO3(s), can be prepared by heating sodium bicarbonate, NaHCO3(s). 2NaHCO3(s) ⇌ Na2CO3(s) + CO2(g)...
Sodium carbonate, Na2CO3(s), can be prepared by heating sodium bicarbonate, NaHCO3(s). 2NaHCO3(s) ⇌ Na2CO3(s) + CO2(g) + H2O(g), Kp = 0.264 at 179 °C If a sample of NaHCO3 is placed in an evacuated flask and allowed to achieve equilibrium at 179 °C, what will the total gas pressure (in atm) be?
Assuming you weighed out a 2.3684 g sample of your unknown, and dissolved and diluted it...
Assuming you weighed out a 2.3684 g sample of your unknown, and dissolved and diluted it as in the procedure below, and it took 35.63 mL of a 0.1025 M HCl titrant to reach the endpoint, what are the weight percents of Na2CO3 and NaHCO3 in your unknown sample? Hints: -Set g Na2CO3 = X -Eqn A: bicarbonate + carbonate = diluted weighted mass (remember, the mass is not 2.3684, you diluted it before you titrated it.Calculate the diluted g...
2.176 g of a solid mixture containing only potassium carbonate (FW = 138.2058 g/mol) and potassium...
2.176 g of a solid mixture containing only potassium carbonate (FW = 138.2058 g/mol) and potassium bicarbonate (FW = 100.1154 g/mol) is dissolved in distilled water. 30.06 mL of a 0.765 M HCl standard solution is required to titrate the mixture to a bromocresol green end point. Calculate the weight percent of potassium carbonate and potassium bicarbonate in the mixture.
2.164 g of a solid mixture containing only potassium carbonate (FW = 138.2058 g/mol) and potassium...
2.164 g of a solid mixture containing only potassium carbonate (FW = 138.2058 g/mol) and potassium bicarbonate (FW = 100.1154 g/mol) is dissolved in distilled water. 32.22 mL of a 0.766 M HCl standard solution is required to titrate the mixture to a bromocresol green end point. Calculate the weight percent of potassium carbonate and potassium bicarbonate in the mixture.
A 2.1782.178 g sample of a solid mixture containing only potassium carbonate (MM=138.2058 g/mol) and potassium...
A 2.1782.178 g sample of a solid mixture containing only potassium carbonate (MM=138.2058 g/mol) and potassium bicarbonate (MM=100.1154 g/mol) is dissolved in distilled water. A volume of 35.59 of a 0.763 M HCl standard solution is required to titrate the mixture to a bromocresol green end point. Calculate the weight percent of potassium carbonate and potassium bicarbonate in the mixture. K2CO3:________________________ KHCO3:__________________________