Question

Consider the following reductions and arrange them in order of decreasing tendency to occur from the given reactions (or lack of reaction) below:

Reductions:

IrCl₆^3- -- Ir

S -- H₂S

HClO₂ -- Cl^-

F₂ -- F-

CeOH³⁺ -- Ce³⁺

Reactions

1.Ir +S -> No Reaction

2. F₂ + Ce³⁺ -> CeOH³⁺ + F^-

3. Ir + HClO₂ -> Cl^- IrCl₆^3-

4. HClO₂ + Ce³⁺ -> No Reactions

Explain how you arrive at your arrangement.

What substance is the strongest reducing agent?

What substance is the weakest reducing agent?

Answer 1

answer :

Ce+3 is the strongest reducing agent

F- is the weakest reducing agent .

explanation :

only two reactions are taking place

2.) F₂ + Ce³⁺ ---------------> CeOH³⁺ + F^-

3.) Ir + HClO₂ ---------------> Cl^- IrCl₆^3-

F2 is the strongest oxidising agent based on standard reduction potential . so F- is the weakest reducing agent .

Ce+3 is strongest reducing agent .

because here Ce⁺³ ------------------> Ce⁺⁴ + e-

        ( oxidation state of Ce in CeOH⁺³ is +4 )