Question

A sheet of gold weighing 8.8 g and at a temperature of 17.4°C is placed flat on a sheet of iron weighing 20.1 g and at a temperature of 58.8°C.What is the final temperature of the combined metals? Assume that no heat is lost to the surroundings.

A 4.42−kg piece of copper metal is heated from 20.5°C to 340.3°C. Calculate the heat absorbed (in kJ) by the metal. The specific heat of copper is 0.385 J/g ·°C.

Answer 1

# Specific heat of gold = 0.129 j /g ⁰C

Specific heat of iron = 0.444 j /g ⁰C

two q's to 0

[(8.8)(0.129)(Final tem - 17.4)] + [(20.1)(0.444)(final tem - 58.8)

(1.1352 final tem - 19.75248) + (8.9244 final tem - 524.7547)

10.0596 final tem = 544.507

final tempreture = 544.507 / 10.0596 = 54. 128⁰C

# 4.42 kg = 4420 gm

T = 340.3 - 20.5 = 319.8 ⁰C

q = mass of copper specific heat of copper T

= 4420 0.385 319.8

q = 544203.66 J = 544.20366 KJ

heat absorbed by metal = 544.20366 KJ