Question

**A sheet of gold weighing** 8.8 g **and at a temperature of** 17.4°C
**is placed flat on a sheet of iron
weighing** 20.1 g
**and at a temperature of**
58.8°C.**What
is the final temperature of the combined metals? Assume that no
heat is lost to the surroundings.**

**A 4.42−kg piece of copper metal
is heated from 20.5**°**C to
340.3**°**C. Calculate the heat absorbed**
(in kJ) **by the metal. The specific heat of copper is
0.385 J/g** ·°**C.**

Answer #1

# Specific heat of gold = 0.129 j /g ^{0}C

Specific heat of iron = 0.444 j /g ^{0}C

two q's to 0

[(8.8)(0.129)(Final tem - 17.4)] + [(20.1)(0.444)(final tem - 58.8)

(1.1352 final tem - 19.75248) + (8.9244 final tem - 524.7547)

10.0596 final tem = 544.507

final tempreture = 544.507 / 10.0596 = 54. 128^{0}C

# 4.42 kg = 4420 gm

T = 340.3 - 20.5
= 319.8 ^{0}C

q = mass of copper specific heat of copper T

= 4420 0.385 319.8

q = 544203.66 J = 544.20366 KJ

heat absorbed by metal = 544.20366 KJ

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