Question

a sheet of nickel weighing 10g and at a temperature of 18C is placed flat on a sheet of iron weighing 20g and at a temperature of 55.6C. What is the final temperature of the combined metals? assume that no heat is lot to the surroundings

Answer 1

The iron sheet is at a higher temperature and will lose heat to the nickel sheet.

                   -qFe = qNi

Let tc = final temperature of the combined metals

s.heat of Fe= 0.45 J/g^oC ,    s.heat of Ni = 0.44J/g^oC

-{20g ( 0.45J/g^oC) x (tc - 55.6 )} ={10g (.44J/g^0C) (tc - 18)

-{ 9tc - 500.4} ={4.4tc -79.2}

500.4 +79.2 = 4.4tc+9tc

579.6 = 13.4tc

tc= 579.6/13.4= 43.25^oC