Question

A.) Balance the following equation and find the Stoichiometry: SiO2+C=Si+CO (I balanced it out as 1SiO2+2C=1Si+2CO and for the Stoiciometry, would it be SiO2=1,C=2, Si=1 and CO=2?)

B.) Determine how many moles and grams of SiO2 and C will be needed to make 25.80mole of Si.

C.) Determine how many moles and grams of waste CO will be produced.

Answer 1

A) You have balanced correctly.

Balanced equation :- SiO2 + 2 C ------> Si + 2 CO

B) Moles of Si formed = 25.80 mol

From reaction, Number of moles of SiO2 reacted = number of moles of Si formed

So number of moles of SiO2 reacted = 25.80 mol

Molar mass of SiO2 = 60.08 g/mol

Mass of SiO2 needed = 60.08 g/mol * 25.80 mol = 1550 g

From Reaction, Moles of C needed = 2 * moles of Si formed = 2 * 25.80 mol = 51.60 mol

Atomic weight of C = 12 g/mol

Mass of C needed = 12 g/mol * 51.60 mol = 619.20 g

C) From reaction, moles of CO formed = 2 * moles of Si formed = 2 * 25.80 mol = 51.60 mol

Molar mass of CO = 28 g/mol

Mass of CO produced = 28 g/mol * 51.60 mol = 1444.80 g