Consider the reaction 2h2 + o2 →2h2o if a mixture of 1.0 mole of H2 and 1.0 mole of O2 is taken, how many grams of H2O can form?
Balanced chemical equation is:
2 H2 + O2 ---> 2 H2O
2 mol of H2 reacts with 1 mol of O2
for 1 mol of H2, 0.5 mol of O2 is required
But we have 1 mol of O2
so, H2 is limiting reagent
we will use H2 in further calculation
Molar mass of H2O,
MM = 2*MM(H) + 1*MM(O)
= 2*1.008 + 1*16.0
= 18.016 g/mol
According to balanced equation
mol of H2O formed = (2/2)* moles of H2
= (2/2)*1
= 1 mol
mass of H2O = number of mol * molar mass
= 1*18.02
= 18.02 g
Answer: 18.0 g
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