how much water can be produced when 1.22g of O2 reacts with H2? 2H2 + O2=2H2O please show work
Molar mass of O2 = 32 g/mol
mass of O2 = 1.22 g
mol of O2 = (mass)/(molar mass)
= 1.22/32
= 0.0381 mol
we have the Balanced chemical equation as:
2H2 + O2=2H2O
From balanced chemical reaction, we see that
when 1 mol of O2 reacts, 2 mol of H2O is formed
mol of H2O formed = (2/1)* moles of O2
= (2/1)*0.0381
= 0.0762 mol
Molar mass of H2O = 2*MM(H) + 1*MM(O)
= 2*1.008 + 1*16.0
= 18.016 g/mol
mass of H2O = number of mol * molar mass
= 0.0762*18.016
= 1.37 g
Answer: 1.37 g
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