The solubility product constant for Zn(OH)2 is Ksp=3.00*10^-16
The formation constant for the hydroxo complex Zn(OH)4^2- is Kf=4.60*10^17
When Zn(OH)2(s) was added to 1.00 L of a basic solution, 1.19
https://www.youtube.com/watch?v=ikbp1Z6tct8
Zn(OH)2 (s) Zn2+ (aq) + 2OH- (aq) Ksp = 3X10-16
Zn 2+(aq) + 4OH- (aq) Zn(OH)42- (aq) Kf = 4.6 x 10 17
-------------------------------------------------------------------------------------------------------------------------------------
Zn(OH)2 (s) + 2 OH- (aq) Zn(OH)42- (aq) Ktot = Ksp x Kf = 165.6
Zn(OH)2 (s) | OH- (aq) | Zn(OH)42- (aq) | |
ni | --- | A | |
nrx | --- | -2(1.19x10-2) | +1.19x10-2 |
nfinal | --- | A - 0.0238 | 1.19x10-2 |
Ktot = [Zn(OH)42-]/[OH]2 = 165.6
Kt = 1.19x10-2 / ( A- 0.0238) = 165.6
A = (1.19x10-2 / 165.6)1/2 + 0.0238 = 0.03228 M
[OH] = A -0.0238 = 0.03228-0.0238 = 8.48E-3
Get Answers For Free
Most questions answered within 1 hours.