A 45-year-old woman named Christine is measured as having the following skinfold thicknesses on the right side of her body: Triceps: 14mm; Thigh: 32mm; Suprailium: 28mm. Estimate her body fat percentage. (Answer to one digit after the decimal point.)
The average weight of a 45 year old woman is around 80 kgs.
Age of the the woman = 45 years
Weight of the woman = 80 kilograms
Skinfold thickness
Triceps = 14 mm
Thigh = 32 mm
Suprailium = 28 mm
Formula for :-
Body fat percentage = 495 /(1.089733 - (0.0009245*s) + (0.0000025*s*s) - (0.0000979*a)) -450
Here s - 3 skin folds of the body , a - age of the woman
Thus the average fat percentage of a 45 year old woman with given skinfold measurement is around 29%.
Thank you. Please do like answer.
Get Answers For Free
Most questions answered within 1 hours.