Question

Dr. Jack Smith of the Fisheries and Wildlife Department at NMSU has hired you to analyze some data that was collected several years and he has not had time to do it himself. He knows that you are enrolled in GENE 320 and have a basic understanding of population genetics. He had done some research on two separate populations of western whiptail lizards. Population 1 was found on the western side of the Organ mountains while population 2 was located on the eastern side of the Organ mountains. At the time, he collected blood samples from individuals in both populations. He analyzed the samples and determined the alleles of the gene for the enzyme α-glycerol-phosphate dehydrogenase (α-GPD). Based upon the number of individuals below, he would like you to calculate the allele and genotypic frequencies of both populations and determine if both populations are in Hardy-Weinberg equilibrium. Please show him all of your work. Please minimize rounding.

Genotype Population 1 Population 2

CC 36 54

CD 92 108

DD   52 38

Answer 1

Answer-

Total population = 3654+ 92108 + 5238 = 101000

Allele frequency

F ( C) = 3654+92108/2

F(C) = 3654 + 46054

= 49708 ÷ 101000

= 0.49

Allele frequency of D should be

F( D) = 1-0.49

= 0.52

But,

F(D) = 5238 + 92108/2

=5238+46054

= 51292 ÷ 10,1000

= 0. 50 .

The allele frequencies do not match .

Genotypic frequency =

CC = p​​​​​​2​​​ = (0.49)2 = 0.24

DD = q​​​​​2 = (0.50)2 = 0.25

CD = 2pq= 2 x 0.24 x 0.25 = 0.12

All the genotypic frequencies should add to 1

0.24 + 0.25+ 0.12 = 0.61.

This population is not in Hardy weinberg equilibrium.

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