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Imagine there is an epistatic gene that controls if the pigment is deposited on the hair...

Imagine there is an epistatic gene that controls if the pigment is deposited on the hair of the mice. There must be at least one dominant epistatic gene (E) for the color to show otherwise the mouse is white. The next questions pertain to the epistatic gene, consider this is a dihybrid cross.

a. Show the Punnett square for a dihybrid cross of two mice that are heterozygotic for both color and the epistatic gene.

b. What percentage of the offspring are white?

c. Why is this different than Mendel's F2 generation with the dihybrid cross pea plants (pea color, pea shape)?

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Answer #1

B_E_ = brown

bbE_ = black

B_ee, bbee = white

A. BbEe × BbEe

Gametes BE Be bE be
BE BBEE brown BBEe brown BbEE brown BbEe brown
Be BBEe brown BBee white BbEe brown Bbee white
bE BbEE brown BbEe brown bbEE black bbEe black
be BbEe brown Bbee white bbEe black bbee white

Phenotypic ratio = 9 : 3 : 4

B. 4/16 × 100 = 25%

C. This is because epistasis is a non Mendelian type of inheritance. The genes involved do not show independent assortment. In this case , recessive allele present at one gene locus is inhibiting the effect of alleles present at other gene locus and this is an example of recessive epistasis.

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