Question

solve the differential equation

y'' +y=(sin^2)x

Answer #1

Note : general solution y(x) = y_{c}(x) +
y_{p}(x).

Solve the first-order linear differential equation:
y ′ + sin ( x ) y = sin ( x ) , y ( 0 ) = 2.

Solve the first order differential equation.
y' - y= sin(x)

Solve the differential equation:
dy/dx = sin(x - y).

Use undetermined coefficients to solve the differential
equation
y'' + y = x sin 2x

dx
+ (x cot y + sin y) dy=0, Solve the differential equation and write
your answer without negative exponents.

solve differential equation ((x)2 - xy +(y)2)dx - xydy
= 0
solve differential equation (x^2-xy+y^2)dx - xydy =
0

Solve the differential equation y"-4y'-12y=sin(2x)

Solve the given differential equation by undetermined
coefficients.
y'' + 2y' + y = 2 cos x − 2x sin x

solve the differential equation
y'=y/x+3x^2+x

Solve the following Differential equations
a) x sin y dx + (x^2 + 1) cos y dy = 0

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