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Elgamal Cryptosystem In the Elgamal cryptosystem, Alice and Bob use p = 17 and g =...

Elgamal Cryptosystem

In the Elgamal cryptosystem, Alice and Bob use p = 17 and g = 3. Alice chooses her secret to be a = 6, so g^a mod p = 3^6 mod 17 = 15. Alice publishes (p,g,g^a mod p) = (17,3,15). Bob sends the ciphertex (7, 6). That is, he chooses a secret 1 ≤ b ≤ p − 1 and tells Alice that g^b ≡ 7 (mod p) and (g^a)^b · m ≡ 6 (mod p). Determine the plaintext m.

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Elgamal Cryptosystem In the Elgamal cryptosystem, Alice and Bob use p = 17 and g = 3. Alice chooses her secret to be a = 6, so g^a mod p = 3^6 mod 17 = 15.

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