Question

Anyone have any skills with Mathematica? If not, show how you'd solve it normally, maybe that will help me understand this problem better.

We are going to start by computing the tangent plane to the ellipsoid

x^2 + 2y^2 + 3z^2 = 1

at the point (x0, y0, z0) = (1/2, 1/6, 5/(6*(Sqrt [3])))

Define the Mathematica function f(x, y, z) = x^2 + 2y^2 + 3z^2, the values x0, y0, z0, as above (stored in variables x0, y0, z0), and verify that f(x0, y0, z0) = 1

Answer 1

1