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Prove that every point on the line y = 6 − x is outside the circle...

Prove that every point on the line y = 6 − x is outside the circle with equation (x + 3)^2 + (y − 1)^2 = 16 (recall that a point (a, b) is outside the circle means that (a + 3)^2 + (b − 1)^2 ≥ 16).

Proof from scratch please!

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