The AFL (Australian Football League) has 18 teams. Each team plays one game per week. Assume a team never plays a given other team more than once. Prove that after 8 weeks, there exists at least 3 teams none of which have played each other.
Total number of team=18
Each team plays one game per week
Two teams required for each game.
Therefore, total number of games in one week
Three team can be choosen out of 18 team
Therefore, possible number of ways of choosen 3 teams out of 18 teams
Possible number of ways of choosen 3 teams out of 18 teams=816
If each pair of three teams in one game , then total number of games in 8 weeks=816
But,there are 8 weeks
Therefore, total number of games play in 8 week
Therefore, it is not possible that each pair of three team play atleast one game.
Hence, at-least 3 teams are there none of which have played each other.
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