Assume X (Miles per hour) is going to be used to predict stopping distance (y)
X Y
10 30
20 40
40 60
56 86
60 90
65 110
Solution :
X | Y | XY | X^2 | Y^2 |
10 | 30 | 300 | 100 | 900 |
20 | 40 | 800 | 400 | 1600 |
40 | 60 | 2400 | 1600 | 3600 |
56 | 86 | 4816 | 3136 | 7396 |
60 | 90 | 5400 | 3600 | 8100 |
65 | 110 | 7150 | 4225 | 12100 |
n | 6 |
sum(XY) | 20866.00 |
sum(X) | 251.00 |
sum(Y) | 416.00 |
sum(X^2) | 13061.00 |
sum(Y^2) | 33696.00 |
Numerator | 20780.00 |
Denominator | 21152.51 |
r | 0.9824 |
r square | 0.9651 |
Xbar(mean) | 41.8333 |
Ybar(mean) | 69.3333 |
SD(X) | 20.6593 |
SD(Y) | 28.4410 |
b | 1.3524 |
a | 12.7569 |
r = 0.9824
The CORRELATION between X and Y is 0.9824
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