Question

A bacteria has a doubling period of 3 days. If there are 3300
bacteria present now, how many will there be in 22 days?

First we must find the daily growth rate *(Don't round up, keep
all the decimal places)* .

The growth rate is _______

Then we use this rate to answer the question.

There will be bacteria _________

Answer #1

solution:

Given that

Bacteria doubling in period of 3 days

Total No.of Bacteria at present (A) = 3300

Time (t) = 22 days

Exponential Growth rate fuction is given by

Y = A b^(t/k)

Where A = current No.of bacteria

b = Increasing factor = 2

k = time for given increasing factor = 3

a) Here, growth rate per each day is b^(1/k)

Growth rate per each day = 2^(1/3) =1.25992104989 , for 0.25992104989 times per day growth rate

b) Y = 3300 * (2^(1/3))^22

=532190.65

~ 532191

Therefore, In 22 days there will be 532191 (approximately) bacteria

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