In 2017, the entire fleet of light‑duty vehicles sold in the
United States by each manufacturer...
In 2017, the entire fleet of light‑duty vehicles sold in the
United States by each manufacturer must emit an average of no more
than 92 milligrams per mile (mg/mi) of nitrogen oxides (NOX) and
nonmethane organic gas (NMOG) over the useful life (150,000 miles
of driving) of the vehicle. NOX ++ NMOG emissions over the useful
life for one car model vary Normally with mean 88 mg/mi and
standard deviation 4 mg/mi.
(a) What is the probability that a single...
In 2017, the entire fleet of light‑duty vehicles sold in the
United States by each manufacturer...
In 2017, the entire fleet of light‑duty vehicles sold in the
United States by each manufacturer must emit an average of no more
than 9090 milligrams per mile (mg/mi) of nitrogen oxides (NOX) and
nonmethane organic gas (NMOG) over the useful life (150,000150,000
miles of driving) of the vehicle. NOX ++ NMOG emissions over the
useful life for one car model vary Normally with mean 8484 mg/mi
and standard deviation 66 mg/mi.
(a) What is the probability that a single...
The data below are daily carbon monoxide emissions, in parts per
million (ppm).
45, 30, 38,...
The data below are daily carbon monoxide emissions, in parts per
million (ppm).
45, 30, 38, 42, 63, 43, 102, 86, 99, 63, 58, 34, 37, 55, 58,
153, 75, 58, 36, 59, 43, 102, 52, 30, 21, 40, 141, 85, 161, 86, 71,
12.5, 20, 4, 20, 25, 170, 15, 20, 15.
Data from DASL
http://lib.stat.cmu.edu/DASL/Datafiles/Refinery.html.
We wish to know if these data suggest that the overall average
daily emission is more than 45 ppm.
(a) Report an appropriate...
When σ (population standard deviation) is unknown
[Critical Value Approach]
The value of the test statistic...
When σ (population standard deviation) is unknown
[Critical Value Approach]
The value of the test statistic t for the sample mean is
computed as follows:
t = with
degrees of freedom d.f. = n – 1
where n is the sample size, µ is the mean of the null
hypothesis, H0, and s is the standard deviation of the
sample.
t is in the rejection
zone: Reject the null hypothesis, H0
t is not in the rejection...
10 In a
normal distribution find the proportion of area between the z
scores of -1.64...
10 In a
normal distribution find the proportion of area between the z
scores of -1.64 and 0.55.
11 In a
normal distribution find the z score(s) that cuts off the middle
70% of the scores.
If families in a small local community have annual incomes
which are normally distributed with a mean of $32,500 and a
standard deviation of $5,000, then determine the percentile rank of
a family with an income of 35,000
6
The length of time a...