A researcher is interested in determining the proportion of current users of a product that are likely to try a new related product. How many persons should be included in a sample if the researcher wants to be 94% certain that the error of estimation does not exceed 5.5%?
how do we know which is the p to plug into formula. In my answers p= .5.
The sample size formula is given as below:
n = p*q*(Z/E)^2
We are given not given the estimate for proportion, so we take
p = 0.5
q = 1 – p = 0.5
[If we are not given the estimate for the population proportion, then we take it as 0.5 by assuming an equal 50-50% chance for success and failure.]
Confidence level = 94%
Critical Z value = 1.8808
(by using z-table)
Margin of error = E = 0.055
The sample size is given as below:
n = p*q*(Z/E)^2
n = 0.5*0.5*(1.8808/0.055)^2
n = 292.3478
Required sample size = 293
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