Question

For these two questions In order to estimate the number of calls to expect at a...

For these two questions In order to estimate the number of calls to expect at a new suicide hotline, volunteers contact a random sample of 35 similar hotlines across the nation and find that the sample mean is 42.0 calls per month and the sample standard deviation is 5.0 calls per month.

Assume that the population standard deviation is unknown. Find the error of estimate for a 90% confidence interval. Group of answer choices 1.39 1.08 1.43 1.10

Assume that the population standard deviation is unknown. What is the upper bound for a 95% confidence interval? Group of answer choices 43.4 44.2 40.3 43.7

Homework Answers

Answer #1

Solution :

Given that,

Point estimate = sample mean = = 42.0

sample standard deviation = s = 5.0

sample size = n = 35

Degrees of freedom = df = n - 1 = 35 - 1 = 34

At 90% confidence level

= 1 - 90%

=1 - 0.90 =0.10

/2 = 0.05

t/2,df = t0.05,34  = 1.691

Margin of error = E = t/2,df * (s /n)

= 1.691 * ( 5.0/ 35)

Margin of error = E = 1.43

The 90% upper confidence interval estimate of the population mean is,

+ E  

= 42.0 + 1.4 = 43.4

upper bound = 43.4

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Question 1 A researcher wishes to find a 90% confidence interval estimate for an unknown population...
Question 1 A researcher wishes to find a 90% confidence interval estimate for an unknown population mean using a sample of size 25. The population standard deviation is 7.2. The confidence factor z α 2for this est Group of answer choices 1.28 1.645 1.96 Question 2 A 90% confidence interval estimate for an unknown population mean μ is (25.81, 29.51). The length of this CI estimate is Group of answer choices 1.96 1.85 3.7 1.645 Question 3 Data below refers...
A simple random sample of 48 calls is monitored at an in-bound call center and the...
A simple random sample of 48 calls is monitored at an in-bound call center and the average length of the calls is 8 minutes. The population standard deviation σ is unknown. Instead the sample standard deviation s is also calculated from the sample and is found to be 4 minutes.     (9 marks) Construct a 99% confidence interval (using the t-distribution) for the average length of inbound calls. What is the margin of error at the 95% confidence level? Do...
In order to estimate the average electric usage per month, a sample of 196 houses was...
In order to estimate the average electric usage per month, a sample of 196 houses was selected and their electric usage was determined. Assume a population standard deviation of 350 kilowatt-hours. If the sample mean is 2000 kWh, what is the 94% confidence interval estimate of the population mean?
The owner of Britten's Egg Farm wants to estimate the mean number of eggs laid per...
The owner of Britten's Egg Farm wants to estimate the mean number of eggs laid per chicken. A sample of 14 chickens shows they laid an average of 17 eggs per month with a standard deviation of 4 eggs per month.   a-1. What is the value of the population mean? (Click to select)It is unknown.417.00 a-2. What is the best estimate of this value? b-1. Explain why we need to use the t distribution. (Click to select)Use the t distribution...
The owner of Britten's Egg Farm wants to estimate the mean number of eggs laid per...
The owner of Britten's Egg Farm wants to estimate the mean number of eggs laid per chicken. A sample of 36 chickens shows they laid an average of 28 eggs per month with a standard deviation of 15 eggs per month.   a-1. What is the value of the population mean? (Click to select)  It is unknown.  28.00  15 a-2. What is the best estimate of this value? b-1. Explain why we need to use the t distribution. (Click to select)  Use the t distribution...
The owner of Britten’s Egg Farm wants to estimate the mean number of eggs produced per...
The owner of Britten’s Egg Farm wants to estimate the mean number of eggs produced per chicken. A sample of 19 chickens shows they produced an average of 24 eggs per month with a standard deviation of 4 eggs per month. (Use t Distribution Table.) a-1. What is the value of the population mean? It is unknown. 24 4 a-2. What is the best estimate of this value? For a 90% confidence interval, what is the value of t? (Round...
1. To estimate the mean of a population with unknown distribution shape and unknown standard deviation,...
1. To estimate the mean of a population with unknown distribution shape and unknown standard deviation, we take a random sample of size 64. The sample mean is 22.3 and the sample standard deviation is 8.8. If we wish to compute a 92% confidence interval for the population mean, what will be the t multiplier? (Hint: Use either a Probability Distribution Graph or the Calculator from Minitab.)
We would like to estimate the mean salary for a given population. In order to do...
We would like to estimate the mean salary for a given population. In order to do that, we would like to take a sample. We want a 95% confidence interval with a margin of error of 400. To estimate the standard deviation of the population, we took a pilot sample, the size of 30, and found the standard deviation of their salaries to be 5000. How many people do we have to ask to create our desired confidence interval (total...
You want to estimate the mean number of chocolate chips in cookies. The average number of...
You want to estimate the mean number of chocolate chips in cookies. The average number of chocolate chips per cookie in a sample of 40 cookies was 23.95, with a sample standard deviation of 2.55. (A) Find a 90% confidence interval for the mean number of chocolate chips using the t-distribution. (B) Find a 90% confidence interval for the mean number of chocolate chips using the standard normal distribution (for this question, assume the population standard deviation is equal to...
An agronomist wanted to estimate the mean weight of a certain fruit (?) in his farm....
An agronomist wanted to estimate the mean weight of a certain fruit (?) in his farm. He selected a random sample of size ?=16, and found that the sample mean ?̅=55 gm and a sample stranded deviation ?= 3 gm. It is assumed that the population is normal with unknown standard deviation (?). a) Find a point estimate for (?). b) Find a 95% confidence interval for the population mean (?).
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT