Following are the numbers of grams of sugar per 100 grams of apple in a random sample of 6 Red Delicious apples. Assume the population is normally distributed. Construct a 95% confidence interval for the standard deviation of the number of grams of sugar. Round the answers to two decimal places.
12.3 12.5 13.3 13.5 11.8 10.6
Confidence interval for population standard deviation is given as below:
Sqrt[(n – 1)*S2 / χ2 α/2, n – 1 ] < σ < sqrt[(n – 1)*S2 / χ2 1 - α/2, n – 1 ]
We are given
Confidence level = 95%
Sample size = n = 6
Degrees of freedom = n – 1 = 5
Sample standard deviation = S = 1.05956
χ2 α/2, n – 1 = 12.8325
χ2 1 - α/2, n – 1 = 0.8312
(By using chi square table)
Sqrt[(n – 1)*S2 / χ2 α/2, n – 1 ] < σ < sqrt[(n – 1)*S2 / χ2 1 - α/2, n – 1 ]
Sqrt[(6 – 1)* 1.05956^2 / 12.8325] < σ < sqrt[(6 – 1)* 1.05956^2 / 0.8312]
0.6614 < σ < 2.5987
Lower limit = 0.66
Upper limit = 2.60
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