The amounts of time employees of a telecommunications company have worked for the company are normally distributed with a mean of 5.6 years and a standard deviation of 1.9 years. Random samples of size 28 are drawn from the population and the mean of each sample is determined. Use the Central Limit Theorem to find the mean and standard error of the mean of the sampling distribution.
(Round to two decimal places as needed).
Solution :
Given that ,
mean = = 5.6
standard deviation = = 1.9
n = 28
sample distribution of sample mean is ,
=
= 5.6
sampling distribution of standard deviation
= / n = 1.9 / 28
= 0.36
Get Answers For Free
Most questions answered within 1 hours.