Question

OLS Regression on Support for Military Response to North Korea
	Coefficient	SE
V2 (20,000 NK deaths)	−0.259***	0.090
V3 (20,000 SK deaths)	−0.341****	0.091
V4 (20,000 NK and SK deaths)	−0.351****	0.089
Female	−0.088	0.065
Age	−0.007**	0.003
Education	−0.074***	0.026
Household Income	0.013	0.022
Interest in Politics	−0.042	0.035
Political Ideology	0.289****	0.019
Served in Military	0.187	0.126
Constant	2.349****	0.201
N	1,025
Adjusted R2	0.213
Note: ****p<0.001, ***p<0.01, **p<0.05, *p<0.10.

The above results come from a survey experiment where respondents were randomly prompted with one of four possible question wordings. V1 involved no mention of casualties, while V2 through V4 mentioned estimates of 20,000 deaths a day in North Korea ("NK" in the table) and/or South Korea ("SK" in the table). Female and served in military are measured as yes = 1, no = 0; age is measured in years; education, household income, and political ideology are measured on a 1-to-7 scale; interest in politics and support for responding militarily to North Korea are measured on a 1-to-5 scale.

What level of support does the regression predict for a 20-year-old female non-veteran who is somewhat interested in politics (that is, at 4 on the relevant scale), has some college but no degree (that is, at 5 on the relevant scale), is in the median household income category, considers herself slightly conservative (that is, at 5 on the relevant scale), and received question version V1? Round your answer to the nearest hundredth.

Answer 1

Support for Military Response to North Korea = 2.349 -0.259*V2 - 0.341*V3 - 0.351*V4 - 0.088*Female - 0.007* Age - 0.074* Education + 0.013 * Household income - 0.042* Interest in politics + 0.289* Political Ideology + 0.187 * Served in military

Given

Question version V1 , Female , Age = 20 , non veteran, interested in politics = 4, some college but no degree = 5

household income category = 4

slightly conservative (that is, at 5 on the relevant scale)

Support for Military Response to North Korea = 2.349 -0.259*0 - 0.341*0 - 0.351*0 - 0.088*1 - 0.007* 20 - 0.074* 5 + 0.013 * 4 - 0.042* 4 + 0.289* 5+ 0.187 * 0 = 3.08