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Assume that the random variable X is normally​ distributed, with mean =59 and standard deviation of...

Assume that the random variable X is normally​ distributed, with mean =59 and standard deviation of 10 compute the probability P(56<X ≤ 68)

Math   Statistics-And-Probability   
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Answer #1

Solution :

Given that ,

mean = = 59

standard deviation = = 10

P(56 < x 68) = P((56 - 59)/ 10) < (x - ) /   (68 - 59) / 10) )

= P(-0.3 < z 0.9)

= P(z 0.9) - P(z < -0.3)

= 0.8159 - 0.3821

= 0.4338

Probability = 0.4338

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