15. Assume that the heights of men are normally distributed with a mean of 70 inches and a standard deviation of 3.5 inches. If 100 men are randomly selected, find the probability that they have a mean height greater than 71 inches. A. 9.9671
Mean, = 70 in
Standard deviation, = 3.5 in
Sample size, n = 100
For sampling distribution of mean, P( < A) = P(Z < )/)
= = 70 in
=
= 0.35 in
P(mean height greater than 71 inches) = P( > 71)
= 1 - P( < 71)
= 1 - P(Z < (71 - 70)/0.35)
= 1 - P(Z < 2.86)
= 1 - 0.9979
= 0.0021
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