Question

A publisher reports that 65% of their readers own a laptop. A marketing executive wants to test the claim that the percentage is actually different from the reported percentage. A random sample of 130 found that 60% of the readers owned a laptop. Determine the P-value of the test statistic. Round your answer to four decimal places.

Answer 1

Here we have to test that

Null hypothesis :

Alternative hypothesis :

where

n = 130

Sample proportion =

Test statistic:

z = -1.20 (Round to 2 decimal)

Test statistic = z = -1.20

P value:

Test is two tailed test.

P value = 2 * P(z < -1.20)

= 2 * 0.1151 (From statistical table of negative z values)

= 0.2301

P value = 0.2301