. An outbreak of food poisoning occurs in a group of adults
who attended a lunch party. The following table contains
summary data.
Status ill not ill
Ate fish 25 14
Did not eat fish 15 46
_________________________________________
Total 40 60
Find the following probability values:
4%
fish.
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4%
eaten.
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Status | Ill | Not Ill | Total |
Ate Fish | 25 | 14 | 39 |
Did not ate fish | 15 | 46 | 61 |
Total | 40 | 60 | 100 |
a) the probability that an adult becomes ill after eating
probability that an adult becomes ill after eating = number of adult becomes ill and ate fish / total adults who ate fish
probability that an adult becomes ill after eating = 25/39
probability that an adult becomes ill after eating = 0.6410
b) The probability that an adult becomes ill if no fish is eaten = number of adult becomes ill and did not ate fish / total adults who did not ate fish
The probability that an adult becomes ill if no fish is eaten = 15/61
The probability that an adult becomes ill if no fish is eaten = 0.2459
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