Question

Write a discussion post : As we have seen, a confidence interval is constructed using the...

Write a discussion post :

As we have seen, a confidence interval is constructed using the form

point estimate±critical value×standard error

where the point estimate is the value calculated from the sample (e.g. a sample mean), the critical value is a cutoff value from the normal distribution, and the standard error measures the variability of sample means. The margin of error is the second part of this formula:

critical value×standard error

which indicates our uncertainty in the estimate.

Confidence intervals are ubiquitous in scientific articles, but they are also common in reporting some types of general news, although they are usually not labeled as "confidence intervals". If you have ever seen the results of a political poll, you may have noticed that along with the main result the polls generally report a margin of error as well.

For this week's post, find a value that is reported in a news source or scientific article using a margin of error. Briefly describe the quantity being estimated, and find the standard error by dividing the margin of error by the critical value (if a confidence level is reported, use that confidence level and qnorm to find the critical value; otherwise, you may assume 95% confidence). What does the standard error tell you about the variability of this estimate?

If you are having trouble finding a value reported with a margin of error, try looking at any news source reporting political polls, or a data-oriented news source such as FiveThirtyEight.

Homework Answers

Answer #1

Sol:

here we have taken data

from

link is:

https://projects.fivethirtyeight.com/trump-approval-ratings/

population proportion who disapprove Donald trump is

p=0.528

point estimate=0.528

z crit for 95%=1.96

margin of error =zcrit*sqrt(p*(1-p)/n

given till day 798

so n=798

margin of error =1.96*sqrt(0.528*(1-0.528)/798)=0.03464

95% confidence interval for true population proportion of voters who disagree trump is

point estimate-margin of error,point estimate+margin of error

0.528-0.03464,0.528+0.03464

0.49336,0.56264

0.49336*100,0.56264*100

=49.3%,56.3%

we are 95% confident that the true population proportion of voters who disagree trump lies in between

49.3% to 56.3%

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Select all the ways that one could correctly write a confidence interval. ( ) point estimate...
Select all the ways that one could correctly write a confidence interval. ( ) point estimate ± margin of error ( ) point estimate ± SE ( ) [0.035, 0.145] ( ) pˆ±1.96*SE From what I've found is that: Confidence intervals are also often reported as: point estimate  ±  margin of error The confidence intervals we have encountered thus far have taken the form: point estimate  ± z* ×SE (z*= zscore) Evaluate the CI and write in the form (___,___). ( CI=Confidence Intervals)...
Ten newborn gorillas are weighed, giving the following data, in lbs. : 35, 37.1, 41, 40.9,...
Ten newborn gorillas are weighed, giving the following data, in lbs. : 35, 37.1, 41, 40.9, 39.5, 38, 29, 27, 30.1, 35.2. a) construct the boxplot for this data b) find the mean and standard deviation of the newborn gorilla weights 16. Typically political polls, where they show the percentage of Americans with certain preferences, have a margin of error of 3%, and a confidence level of 95%. What sample size is needed by ABC News if they want just...
Using a T-Interval on your calculator to find a 95% confidence interval estimate of a mean...
Using a T-Interval on your calculator to find a 95% confidence interval estimate of a mean when the sample mean from a sample of 35 individuals is 132.5 and the sample standard deviation is 14.7, what is the resulting margin of error?
Assume that you want to construct a​ 95% confidence interval estimate of a population mean. Find...
Assume that you want to construct a​ 95% confidence interval estimate of a population mean. Find an estimate of the sample size needed to obtain the specified margin of error for the​ 95% confidence interval. The sample standard deviation is given below. Margin of errors=​$6​, standard deviation=​$22 The required sample size is __
c. Confidence Interval given the sample standard deviation: 5. Confidence Interval, σ is not known or...
c. Confidence Interval given the sample standard deviation: 5. Confidence Interval, σ is not known or n<30. For a group of 20 students taking a final exam, the mean heart rate was 96 beats per minute and the standard deviation was 5. Find the 95% confidence interval of the true mean.   e) Find the critical value: f) Find the margin of error: E =tα/2sn√ g) Find the confidence interval: CI = x−± E. h) Write the conclusion.
For this term, we will create confidence intervals to estimate a population value using the general...
For this term, we will create confidence intervals to estimate a population value using the general formula: sample estimator +/- (reliability factor)(standard error of the estimator) Recall that the (reliability factor) x (standard error of the estimator)= margin of error (ME) for the interval. The ME is a measure of the uncertainty in our estimate of the population parameter. A confidence interval has a width=2ME. A 95% confidence interval for the unobserved population mean(µ), has a confidence level = 1-α...
This is under "Confidence Intervals for a Mean": Assume that a sample is used to estimate...
This is under "Confidence Intervals for a Mean": Assume that a sample is used to estimate a population mean μ. Find the margin of error M.E. that corresponds to a sample of size 12 with a mean of 46.8 and a standard deviation of 13.2 at a confidence level of 90%. Report ME accurate to one decimal place because the sample statistics are presented with this accuracy. M.E. = ? Answer should be obtained without any preliminary rounding. However, the...
A 95 % confidence interval of 16.2 months to 50.2 months has been found for the...
A 95 % confidence interval of 16.2 months to 50.2 months has been found for the mean duration of imprisonment, mu , of political prisoners of a certain country with chronic PTSD. a. Determine the margin of error, E. b. Explain the meaning of E in this context in terms of the accuracy of the estimate. c. Find the sample size required to have a margin of error of 11 months and a 99 % confidence level. (Use sigma equals...
We want to estimate π using a confidence interval that has a 3% margin of error,...
We want to estimate π using a confidence interval that has a 3% margin of error, and we want to have 99% confidence that our interval captures π. We think that π is between .4 and .6. What sample size should we use?
Use the confidence level and sample data to find a confidence interval for estimating the population...
Use the confidence level and sample data to find a confidence interval for estimating the population mean. A local telephone company randomly selected a sample of 679 duration of calls. The a sample mean amount was 6.81 min with a population standard deviation of 5.1 min. Construct a confidence interval to estimate the population mean of pulse rate if a confidence level is 99% . Initial Data: E(margin of error result value) = CI(population mean confidence interval result value)=
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT