If n=20, ¯ x (x-bar)=44, and s=15, construct a confidence interval at a 98% confidence level. Assume the data came from a normally distributed population.
Give your answers to one decimal place. < μ <
Solution :
t /2,df = 2.539
Margin of error = E = t/2,df * (s /n)
= 2.539 * (15 / 20)
Margin of error = E = 8.5
The 98% confidence interval estimate of the population mean is,
- E < < + E
44 - 8.5 < < 44 + 8.5
35.5 < < 52.5
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