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Suppose 9 out of 10 homes have televisions, what is the probability that at least 1090...

Suppose 9 out of 10 homes have televisions, what is the probability that at least 1090 homes out of a sample of 1200 homes will have a TV? (be careful about decimal rounding and continuity corrections)
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Answer #1

Let X is a random variable that counts the homes having televisions.Then X will follow binomial distribution with parameters n and p.

Now probability of having television=9/10=0.9=p

And n=1200

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