Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Round your answer to four decimal places.)
μ = 24; σ = 3.9
P(x ≥ 30) =
Solution :
Given that,
mean = = 24
standard deviation = = 3.9
P (x 30 )
= 1 - P (x 30 )
= 1 - P ( x - / ) ( 30 - 24 / 3.9 )
= 1 - P ( z 6 / 3.9 )
= 1 - P ( z 1.54)
Using z table
= 1 - 0.9382
= 0.0618
Probability = 0.0618
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