Consider the data set below.
x | 4 | 6 | 3 | 8 | 7 | 6 |
y | 1 | 3 | 9 | 1 | 8 | 6 |
For a hyopthesis test, where H0:?1=0 and H1:?1?0, and using ?=0.01, give the following:
(a) The test statistic t=
(b) The degree of freedom df=
(c) The rejection region |t|>
X | Y | (X-Mx)^2 | (Y-My)^2 | (X-Mx)(Y-My) | Y' | (Y-Y')^2 | |
4 | 1 | 2.777777778 | 13.44444 | 6.111111 | 5.596154 | 21.12463 | |
6 | 3 | 0.111111111 | 2.777778 | -0.55556 | 4.480769 | 2.192678 | |
3 | 9 | 7.111111111 | 18.77778 | -11.5556 | 6.153846 | 8.100592 | |
8 | 1 | 5.444444444 | 13.44444 | -8.55556 | 3.365385 | 5.595044 | |
7 | 8 | 1.777777778 | 11.11111 | 4.444444 | 3.923077 | 16.6213 | |
6 | 6 | 0.111111111 | 1.777778 | 0.444444 | 4.480769 | 2.308062 | |
Mean | 5.666667 | 4.66667 | |||||
Sum | 34 | 28 | 17.33333333 | 61.33333 | -9.66667 | 55.94231 |
Y'=b0+b1*X
Standard error:
Standard error for coefficient:
The test statistic:
b) The degree of freedom= n-2=4
c) Rejection region:
|t| > 4.6040949
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