IQ is normally distributed with a mean of 100 and a standard
deviation of 15.
Solution :
(a)
P(x < 95) = P[(x - ) / < (95 - 100) / 15]
= P(z < 0.33)
= 0.629
62.9%
(b)
P(x < 125) = P[(x - ) / < (125 - 100) / 15]
= P(z < 1.67)
= 0.953
95.3%
(c)
P(x < 110) = P[(x - ) / < (110 - 100) / 15]
= P(z < 0.67)
= 0.7486
449
(d)
P(x < 140) = P[(x - ) / < (140 - 100) / 15]
= P(z < 2.67)
= 0.9962
598
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