Your friend wants to play a game with a pair of dice. You win if the sum of the top faces is 5, 6, 7, or 8. The winner pays the loser $1 each game. Should you play?
Total number of ways = 36
Number of ways of of getting sum 2 = 1 i.e(1,1)
Number of ways of of getting sum 3 = 2 i.e (1,2) (2,1)
Number of ways of of getting sum 4 = 3 i.e (1,3) (2,2) (3,1)
Number of ways of of getting sum 9 = 4 i.e (4,5) (5,4) (6,3) (3,6)
Number of ways of of getting sum 10 = 3 i.e (6,4) (4,6) (5,5)
Number of ways of of getting sum 11 = 2 i.e (6,5) (5,6)
Number of ways of of getting sum 12 =1 i.e (6,6)
Number of unfavourable cases = 16
Number of favourable cases = 20
Probability of winning $1 = 20/36
Probability of losing $1 = 16/36
E(X) = 1*(20/36) - 1*(16/36) = 1/9
since expected value is positive
we should play the game
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