We have 7 cards labeled 1 to 7 and we draw 4 of them. Let X be the minimum number among our 4 cards. Find the expected value of X.
These are the following outcomes, where X = min(x1,x2,x3,x4)
x1 | x2 | x3 | x4 | X |
1 | 2 | 3 | 4 | 1 |
1 | 2 | 3 | 5 | 1 |
1 | 2 | 3 | 6 | 1 |
1 | 2 | 3 | 7 | 1 |
1 | 2 | 4 | 5 | 1 |
1 | 2 | 4 | 6 | 1 |
1 | 2 | 4 | 7 | 1 |
1 | 2 | 5 | 6 | 1 |
1 | 2 | 5 | 7 | 1 |
1 | 2 | 6 | 7 | 1 |
1 | 3 | 4 | 5 | 1 |
1 | 3 | 4 | 6 | 1 |
1 | 3 | 4 | 7 | 1 |
1 | 3 | 5 | 6 | 1 |
1 | 3 | 5 | 7 | 1 |
1 | 3 | 6 | 7 | 1 |
1 | 4 | 5 | 6 | 1 |
1 | 4 | 5 | 7 | 1 |
1 | 4 | 6 | 7 | 1 |
1 | 5 | 6 | 7 | 1 |
2 | 3 | 4 | 5 | 2 |
2 | 3 | 4 | 6 | 2 |
2 | 3 | 4 | 7 | 2 |
2 | 3 | 5 | 6 | 2 |
2 | 3 | 5 | 7 | 2 |
2 | 3 | 6 | 7 | 2 |
2 | 4 | 5 | 6 | 2 |
2 | 4 | 5 | 7 | 2 |
2 | 4 | 6 | 7 | 2 |
2 | 5 | 6 | 7 | 2 |
3 | 4 | 5 | 6 | 3 |
3 | 4 | 5 | 7 | 3 |
3 | 4 | 6 | 7 | 3 |
3 | 5 | 6 | 7 | 3 |
4 | 5 | 6 | 7 | 4 |
PMF of X is:
Hence, expected value of X is:
1*20/35 + 2*10/35 + 3*4/35 + 4*1/35 = 56/35
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