Question

. Of 104 adults selected randomly from one town, 76 have health insurance. a. Find a...

. Of 104 adults selected randomly from one town, 76 have health insurance.
a. Find a 95% confidence interval for the true proportion of all adults in the town who have health insurance. (Do this by hand and show all calculations. You can use StatCrunch to check.)
b. Interpret your confidence interval in the context of the problem.
c. What is the margin of error?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Use the one-proportion z-interval procedure to find the required confidence interval. Of 98 adults selected randomly...
Use the one-proportion z-interval procedure to find the required confidence interval. Of 98 adults selected randomly from one town, 64 have health insurance. Find a 90% confidence interval for the proportion of all adults in the town who have health insurance. Group of answer choices 0.541 to 0.765 0.574 to 0.732 0.559 to 0.747 0.529 to 0.777
Flu Season: In a sample of 76 adults selected randomly from one town, it is found...
Flu Season: In a sample of 76 adults selected randomly from one town, it is found that 12 of them have been exposed to a particular strain of the flu. Find the P-value for a test to reject the claim that the proportion of all adults in the town that have been exposed to this strain of the flu is 8%.
Of 147 adults selected randomly in one town, it was found that 31 of them smoke....
Of 147 adults selected randomly in one town, it was found that 31 of them smoke. What is the 95% confidence interval for the proportion of people in this town who smoke.
Of 245 employees selected randomly from one company, 12.11% of them commute by carpooling. a. Construct...
Of 245 employees selected randomly from one company, 12.11% of them commute by carpooling. a. Construct a 90% confidence interval for the true percentage of all employees of the company who carpool. b. Interpret your confidence interval in the context of the problem. c. What is the margin of error?
A researcher in a small town is interested in estimating the true proportion of adults in...
A researcher in a small town is interested in estimating the true proportion of adults in the town who smoke. 215 adults were randomly selected from the town, and it was found that 36 of them smoke. We would like to construct a 90% confidence interval estimate for the true proportion of adults in the town that smoke. please show work! thanks. What are the values of, , and  (Round  and  to three decimal places if needed.) = _______________                 = _______________ = _______________                 = _______________...
In a recent poll of 100 randomly selected adults in the United States, 82 had obtained...
In a recent poll of 100 randomly selected adults in the United States, 82 had obtained a high school diploma. Complete the steps below: a) What is the sample proportion? b) How are the conditions of the Central Limit Theorem met for this scenario? c) What is the margin of error for a 95% confidence interval? Round to 3 places. The margin of error formula is 1.96p^(1−p^)n. d) What is the 95% confidence interval? Round to 3 places.   e) Would...
In a recent poll of 50 randomly selected adults in the U.S., 14 were able to...
In a recent poll of 50 randomly selected adults in the U.S., 14 were able to name ten or more presidents. a) What is the sample proportion? b) What is the margin of error for a 95% confidence interval? (round to three places) c) What is the 95% confidence interval for this scenario? (round to three places) d) Would you support 35% as possible population proportion of U.S. adults who can name ten or more presidents? Why or why not?
Gallup poll consisted of 1012 randomly selected adults who were asked whether or not cloning of...
Gallup poll consisted of 1012 randomly selected adults who were asked whether or not cloning of humans should be allowed. 901 of the adults surveyed said that cloning should not be allowed. Construct a 98% confidence interval to estimate the true percentage of all adults who hold this belief. 1. State the Parameter 2. Find the point estimate 3. Check assumptions 4.Find the critical value 5. Find the margin of error 6. Find the confidence interval limits
In a Pew Research Center poll of 745 randomly selected adults, 589 said that it is...
In a Pew Research Center poll of 745 randomly selected adults, 589 said that it is morally wrong to not report all income on tax returns. a.   Construct a 95% confidence interval estimate of the percentage of all adults who have that belief, and then write a statement interpreting the confidence interval.    76.1% - 82% b.   Assume that you must conduct a new poll to determine the percentage of adults who believe that it is morally wrong to not...
An October 2011 CBS News Poll on illegal immigrants interviewed 1012 randomly selected American adults. Of...
An October 2011 CBS News Poll on illegal immigrants interviewed 1012 randomly selected American adults. Of those in the sample, 688 said that they “oppose allowing the children of illegal immigrants to attend state college at the lower tuition rate of state residents.” Although the samples in national polls are not SRSs, they are similar enough that our method gives approximately correct confidence intervals. a) Find the 99% confidence interval for the proportion of adults who “oppose allowing the children...