In a certain population, body weights are normally distributed with a mean of 152 pounds and a standard deviation of 26 pounds. How many people must be surveyed if we want to estimate the percentage who weigh more than 180 pounds? Assume that we want 96% confidence that the error is no more than 4 percentage points.
Mean, = 152 pounds
Standard deviation, = 26 pounds
Margin of Error < 0.04
< 0.04
< 0.04
<
> 1334.905
Squaring both sides
n > 1781971.359
So At least 1781972 people must be surveyed.
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