At one large university, freshman accounts 30% of the student body, if a group of 12 students is random chosen by the school news paper to comment on text book prices, what is the probability that at most three of the students are freshme?
Solution
Given that ,
p = 0.30
1 - p = 0.70
n = 12
Using binomial probability formula ,
P(X = x) = ((n! / x! (n - x)!) * px * (1 - p)n - x
P(X 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)
= ((12! / 0! (12 - 0)!) * 0.300* (0.70)12 - 0 + ((12! / 1! (12 - 1)!) * 0.301* (0.70)12 - 1 + ((12! / 2! (12 - 2)!) * 0.302* (0.70)12 - 2 + ((12! / 3! (12 - 3)!) * 0.303* (0.70)12 - 3
= 0.0138 + 0.0712 + 0.1678 + 0.2397
Probability = 0.4925
Get Answers For Free
Most questions answered within 1 hours.