Question

Assume that a sample is used to estimate a population mean μμ. Find the 95% confidence interval for a sample of size 901 with a mean of 34.3 and a standard deviation of 11.9. Enter your answer as a tri-linear inequality accurate to 3 decimal places.

< μ <

Answer 1

Solution :

Given that,

t /2,df = 1.963

Margin of error = E = t/2,df * (s /n)

= 1.963 * (11.9 / 901)

Margin of error = E = 0.778

The 95% confidence interval estimate of the population mean is,

- E < < + E

34.3 - 0.778 < < 34.3 + 0.778

33.522 < < 35.078