Question

A sample of 90 women is​ obtained, and their heights​ (in inches) and pulse rates​ (in beats per​ minute) are measured. The linear correlation coefficient is 0.285 and the equation of the regression line is ModifyingAbove y with = 17.6 + 0.930 x​, where x represents height. The mean of the 90 heights is 63.4 in and the mean of the 90 pulse rates is 75.7 beats per minute. Find the best predicted pulse rate of a woman who is 75 in tall. Use a significance level of alpha = 0.01.

The best predicted pulse rate of a woman who is 75 in tall is ? beats per minute.

Critical Values of the Pearson Correlation Coefficient r			​
n	α=0.05	α=0.01
4	0.950	0.990
5	0.878	0.959
6	0.811	0.917
7	0.754	0.875
8	0.707	0.834
9	0.666	0.798
10	0.632	0.765
11	0.602	0.735
12	0.576	0.708
13	0.553	0.684
14	0.532	0.661
15	0.514	0.641
16	0.497	0.623
17	0.482	0.606
18	0.468	0.590
19	0.456	0.575
20	0.444	0.561
25	0.396	0.505
30	0.361	0.463
35	0.335	0.430
40	0.312	0.402
45	0.294	0.378
50	0.279	0.361
60	0.254	0.330
70	0.236	0.305
80	0.220	0.286
90	0.207	0.269
100	0.196	0.256
n	α=0.05	α=0.01

Answer 1

Answer:

Given Data

A sample of 90 women is​ obtained, and their heights​ (in inches) and pulse rates​ (in beats per​ minute) are measured.

The mean of the 90 heights is 63.4 in and

the mean of the 90 pulse rates is 75.7 beats per minute.

The linear correlation coefficient is (r) = 0.285

the equation of the regression line = 17.6 + 0.930 x​,

where x represents height. & y represents plase rate.

When height x = 75 inches,

Predicted pluse rate ,

= 17.6 +0.930(75)

= 17.6 + 69.75

= 87.35

  The best predicted pulse rate of a woman who is 75 in tall is 87.35 beats per minute.

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