In a survey, 29 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $31 and standard deviation of $14. Estimate how much a typical parent would spend on their child's birthday gift (use a 99% confidence level). Give your answers to one decimal place. Provide the point estimate and margin or error.
Given that,
point estimate = 31
s =14
n = 29
Degrees of freedom = df = n - 1 =29 - 1 = 28
At 99% confidence level the t is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
t /2 df = t0.005, = 2.763 ( using student t table)
Margin of error = E = t/2,df * (s /n)
= 2.763* ( 14/ 29) =7.2
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